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valentina_108 [34]
2 years ago
7

Jane evaluates x2-3x+5 for x=-2 below.

Mathematics
1 answer:
denis-greek [22]2 years ago
6 0

Answer: Jane incorrectly evaluated (-2)² in step 2.

Step-by-step explanation:

(-2)^{2}=4, not -4.

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What is the value of s?<br> S=
barxatty [35]

Answer:

s = 1

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 5 , then

sum = 180° × 3 = 540°

sum the interior angles and equate to 540

39s + 129 + 79 + 145 + 148 = 540 , that is

39s + 501 = 540 ( subtract 501 from both sides )

39s = 39 ( divide both sides by 39 )

s = 1

6 0
3 years ago
A rectangular cooler is 18 inches long, 12 inches wide, and 12 inches deep, what is the volume of the cooler?
MissTica
The volume is 2592 inches
7 0
3 years ago
Determine the intercepts of the line2x+5y=-6
noname [10]

Answer:

y=−2/5x−6/5

Step-by-step explanation:

4 0
3 years ago
. Suppose you plan to make a box that will hold exactly 40 one-inch cubes. Give the dimensions (ex: 1in x 1in x 40in) of 3 possi
stiks02 [169]

Answer:

The dimensions of the three possible boxes are;

Box 1:  2 inches length by 4 inches width by 5 inches height

Box 2:  2 inches length by 2 inches width by 10 inches height

Box 3:  8 inches length by 1 inch width by 5 inches height

Step-by-step explanation:

The dimensions of the required box = 40 in³

Therefore, a box that will hold all the cubes will have a dimension given as follows;

Length, l × Width, w × Height, h = 40 in.³

We therefore, look for possible dimensions of l, w, h, however to make is faster, we note that l × w = base area, BA, hence we look for the factors 40 thus;

BA × h        ≡  l × w × h

8  × 5 = 40 ≡ 2 × 4 × 5 = 40

4 × 10 = 40 ≡ 2 × 2 × 10 = 40

8 × 5 = 40 ≡ 8 × 1 × 5 = 40

Hence we have our three possible boxes as follows;

Box 1: Length = 2 inches, width = 4 inches and height = 5 inches

Box 2: Length = 2 inches, width = 2 inches and height = 10 inches

Box 3: Length = 8 inches, width = 1 inches and height = 5 inches.

4 0
3 years ago
If A, B, and C are mutually exclusive events with P(A) 0.2, P(B): 0.3, and P(C) 0.4, determine the following probabilities:
Lesechka [4]

Answer:

a. 0.9

b. 0.024

c. 0.06

d. 0.2

e. 0.336

Step-by-step explanation:

Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).

a.

P (A U B U C)=P(A)+P(B)+P(C)

P (A U B U C)=0.2+0.3+0.4=0.9

b.

P(A∩B∩C)=P(A)*P(B)*P(C)

P(A∩B∩C)=0.2*0.3*0.4=0.024

c.

P(A∩B)=P(A)*P(B)

P(A∩B)=0.2*0.3=0.06

d.

P[(AUB)∩C]=P(AUB)*P(C)

P(AUB)=P(A)+P(B)=0.2+0.3=0.5

P[(AUB)∩C]=0.5*0.4=0.20

e.

P(A')=1-P(A)=1-0.2=0.8

P(B')=1-P(B)=1-0.3=0.7

P(C')=1-P(C)=1-0.4=0.6

P(A'∩B'∩ C')=P(A')*P(B')*P(C')

P(A'∩B'∩ C')=0.8*0.7*0.6=0.336

7 0
3 years ago
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