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Nady [450]
3 years ago
9

A rectangular cooler is 18 inches long, 12 inches wide, and 12 inches deep, what is the volume of the cooler?

Mathematics
1 answer:
MissTica3 years ago
7 0
The volume is 2592 inches
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The volume of a cylinder is 347.6cm cube. If the area of the base 34.76cm squared, what is the height?
34kurt

Answer:

115.3333

Step-by-step explanation:

346/3

Hope this helps. :)

7 0
3 years ago
Which function below is the inverse of f(x) = The quantity of three x plus five, over seven?
Nastasia [14]
Given function: f(x) = (3x+5)/7

y = f(x) so it's the same as y = (3x+5)/7

Swap every copy of x and y to get x = (3y+5)/7

Solve for y to get....
x = (3y+5)/7
7x = 7*(3y+5)/7
7x = 3y+5
7x-5 = 3y+5-5
7x-5 = 3y
3y = 7x-5
3y/3 = (7x-5)/3
y = (7x-5)/3

So the inverse function is f^(-1)(x) = (7x-5)/3

Answer is choice A


5 0
4 years ago
Read 2 more answers
pleasee helpp answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!!!!!
Lelu [443]

Answer:

BDE

or

EDB

Step-by-step explanation:

Make the marked angle, D, your center point. Find the two other points of the angle, E and B. write them in order, forwards and backwards.

6 0
3 years ago
The perimeter of a rectangle is equal to 20. If the length is tripled and the width is doubled, the new perimeter is increased b
valkas [14]

16 inches in the length

3 0
3 years ago
Six more than the quotient of a number and 4 is 3
Lera25 [3.4K]
We presume you want to find the number.

Let n represent the number.
  6 + n/4 = 3 . . . . . . . 6 more than the quotient of a number and 4 is 3.
To solve this, we "undo" what is done to the number. First we undo the addition of 6 by adding its opposite, -6. We add -6 to both sides of the equation so the equal sign remains valid.
  6 -6 +n/4 = 3 -6
  n/4 = -3 . . . . . . . . simplify
Now, we need to undo the division by 4. We do that by multiplying by 4. Again, we must do that to both sides of the equation so the equal sign remains valid.
  4(n/4) = 4(-3)
  n(4/4) = -12
  n = -12

The number is -12.
3 0
3 years ago
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