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2 years ago

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Mathematics

1 answer:

Leona [35]2 years ago

8 0

Answer:

neihwysiwyiwewgeyevehw

Step-by-step explanation:

how to be a great day of school and I have a great day of school and I have a great day of school and I have a great day of school and I have a great day of school and I have a

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Show your work<br><br> v= pi(3.14)r^2h

ddd [48]

Answer: 2000.18 unit^3

Step-by-step explanation:

radius = 14 / 2 = 7

V of cylinder = π x r^2 x h

= 3.14 x 7^2 x 13

= 3.14 x 49 x 13

= 2000.18 unit^3

8 0

1 year ago

HERE IS THE TEXT THERE IS MORE THO

Ostrovityanka [42]

Answer:

What exactly is this for?

8 0

3 years ago

A scientist need 10 L of a 20% acid solution for an experiment where she had only a 5% solution and a 40% solution to the neares

andrezito [222]

Answer:

Amount of 5% solution = 5.7 Litres

Amount of 40% solution = 4.3 Litres

Step-by-step explanation:

First, of all, let x be the amount of 5% solution used

Since, the scientist needs 10 L of solution, then;

Let 10 - x be the amount of 40% solution used

Now, we are told that she needs 10 L of a 20% acid solution.

This means that;

5%x + 40%(10 - x) = 20%(10).

Simplifying this gives;

0.05x + 0.40(10 - x) = 0.20 × 10

Expanding the bracket gives;

0.05x + 4 - 0.4x = 2

0.4x - 0.05x = 4 - 2

0.35x = 2

x = 2/0.35

x ≈ 5.7 litres

Thus, she will need to mix 5.7 liters of the 5% solution.

Since 10 - x be the amount of 40% solution used , then;

the amount of 40% solution = 10 - 5.7 = 4.3 litres

4 0

4 years ago

Help plz:))) I’ll mark you BRAINLIEST I am really struggling with this question plz help and will mark you BRAINLIEST

SIZIF [17.4K]

Answer:

Grace

Step-by-step explanation:

We have to look at the bottom 2 angles, the bigger the angle the wider it is. For Hector, his R angle is 50 degrees and it's 14 wide, but his R angle is 60 degrees, bigger than 50 degrees, and yet the it's only 12.5 wide which is smaller than 14. Grace got it right, 60 degrees is bigger than 50 so it's only natural for it to be wider too.

5 0

3 years ago

Kite EFGH is inscribed in a rectangle such that F and H are midpoints and EG is parallel to the side of the rectangle. Which sta

andrew11 [14]

Answer:

<h3>C.) The area of EFGH is always ¹/₂ of the area of the rectangle. </h3>

Step-by-step explanation:

If EG is parallel to the side of the rectangle then lenght of EG is equal to width of rectangle.

If F and H are midpoints of sides of rectangle then FH is parallel to the side of rectangle {wich is perpendicular to the side parallel to EG}. That means the lenght of FH is equal to lenght of rectangle, and FH is perpendicular to EG.

Then FH is sum of hights of triangles EFG and EHG $(FH=H_{_{\Delta EFG}}+H_{_{\Delta EHG}})$ , and the area of EFGH is sum of areas of triangles EFG and EHG $(A_{kite}=P_{_{\Delta EFG}}+P_{_{\Delta EHG}})$ .

So the area of the rectangle: $\bold{A_{rectangle}=EG\cdot FH}$

The area of the kite:

$A_{kite}=P_{_{\Delta EFG}}+P_{_{\Delta EHG}}\\\\A_{kite}=\frac12 EG\cdot H_{_{\Delta EFG}}+\frac12 EG\cdot H_{_{\Delta EHG}}\\\\ A_{kite}=\frac12 EG\cdot (H_{_{\Delta EFG}}+H_{_{\Delta EHG}})\\\\A_{kite}=\frac12 EG\cdot FH\\\\A_{kite}=\frac12 A_{rectangle}$

No matter the height of the triangles, so no matter the location of the EG

4 0

4 years ago