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Stella [2.4K]
3 years ago
5

Help plz:))) I’ll mark you BRAINLIEST I am really struggling with this question plz help and will mark you BRAINLIEST

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

Grace

Step-by-step explanation:

We have to look at the bottom 2 angles, the bigger the angle the wider it is. For Hector, his R angle is 50 degrees and it's 14 wide, but his R angle is 60 degrees, bigger than 50 degrees, and yet the it's only 12.5 wide which is smaller than 14. Grace got it right, 60 degrees is bigger than 50 so it's only natural for it to be wider too.

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Find the area. Round to the nearest hundredth if necessary
snow_lady [41]

Answer:

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Step-by-step explanation:

a=3.14 x 44

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they have given you diameter so, it is simply pie x diameter

or 3.14 x 44

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3 years ago
Help: see picture for information. How much will Jerry have to pay if he wants to pay as little money as possible?
wolverine [178]
105 is the correct answer

5 0
4 years ago
Read 2 more answers
Write the equation of a parabola that has a vertex of (-2,5.5) and passes through the point (-2.5,2.5).
vekshin1

The equation of a parabola that has a vertex of (-2, 5.5) and passes through the point (-2.5, 2.5) is  y=-12(x+2)^2+5.5

The vertex form of the equation of a parabola is:

y=a(x-h)^2+k

where (h, k) is the vertex of the parabola

(x, y) is the point that the parabola passes through

The vertex, (h, k) = (-2, 5.5)

The point, (x, y) = (-2.5, 2.5)

Substitute h = -2, k = 5.5, x = -2.5, and y = 2.5 into the equation to solve for a.

2.5=a(-2.5-(-2))^2+5.5\\\\2.5=a(-2.5+2)^2+5.5\\\\2.5-5.5=a(-2.5+2)^2\\\\-3=a(-0.5)^2\\\\-3=0.25a\\\\a = \frac{-3}{0.25} \\\\a = -12

Therefore, the equation of the parabola is:

y=-12(x-(-2))^2+5.5\\\\y=-12(x+2)^2+5.5

Learn more here: brainly.com/question/25667732

5 0
3 years ago
Help me on this someone
telo118 [61]

Answer:

how to get a mean of the data in the morning and after some time

6 0
3 years ago
Simplify this question please im really confused
Gemiola [76]

Answer:

option A

Step-by-step explanation:

\frac{x^a}{x^b} = x^{a-b} , z^0 = 1

So,

\frac{18x^5 y}{6xy^8z^0} = \frac{18}{6} \times x^{5 -1} \times y^{1-8} = 3 x^4 \times y^{-7} = \frac{3x^4}{y^7}

8 0
3 years ago
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