Dr/dt= 8cmM-¹
dA/dt = ?
but A= πr²
so dA/dr =2πr
but recall
dA/dt = dA/dr • dr/dt
dA/dt = 2πr • 8cmM-¹
dA/dt = 2×π×39 ×8 = 624cm²M-1
Answer:452.16m^2
Step-by-step explanation:
C=2πr
75.36m=2×3.14×r
75.36m=6.28r
r=12m
Area=πr^2
A=3.14×12m×12m
A=452.16m^2
Hey
Dftackle,
Lets solve your problem
step by step. To solve the problem we have analyze the question carefully<span>.
As we are aware: A</span><span>t an auto dealership, 8 new cars of different colors are randomly lined up in front of the building.
Therefore, lets use a variable "c" to represent the </span><span>different colors of cars as they are randomly lined up in front of the <span>auto dealership.
We know that there are 8 new cars, so
![\dfrac{c}{8}](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bc%7D%7B8%7D%20)
can represent this statement.
Now lets
examine the next line.
</span>We have to find </span><span>the
probability of the first car being
red, the second car being
blue, and the third car being
black.
Since we are only given three cars, our
fraction changes to : </span>
![\dfrac{3}{8}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B3%7D%7B8%7D%20)
.
As a result, the probability of the
first car being red, the
second car being blue, and the
third car being <span>
black is <span>
![\dfrac{3}{8}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B3%7D%7B8%7D%20)
because we do not know any more information about the
remaining cars.
Hope this helps,
</span>
</span>
AnthrαX
He edge length would be 24
don't understand your question