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creativ13 [48]
3 years ago
15

Are the two figures congruent (I don’t know if they are because one is rotated)

Mathematics
2 answers:
Alborosie3 years ago
7 0

Answer:

Δ HGF ≅ Δ JLK

Step-by-step explanation:

Consider the angle- side- angle postulate

∠ HGF = ∠ JLK ← angle

GF = LK ← side

∠ GFH = ∠ LKJ ← angle

Thus Δ HGF is congruent to Δ JLK by ASA postulate

Vladimir79 [104]3 years ago
4 0

Answer:

Yes they are

Step-by-step explanation:

Conguent shapes are still conguent even if rotated and flipped. As long as their angles and length of sides are the same, they are congruent

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Find the value of x and y in parallelogram WXYZ.
navik [9.2K]

Answer:

x = 13, y = 7

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, thus

x - 7 = 6 ( add 7 to both sides )

x = 13

and

2y - 6 = 8 ( add 6 to both sides )

2y = 14 ( divide both sides by 2 )

y = 7

3 0
3 years ago
Simplify 0.5x-2y > 3
egoroff_w [7]

I will assume you want it in the form of y>mx+b

0.5x-2y>3

0.5x-3>2y

0.25x-1.5>y

4 0
3 years ago
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4. Which of the following represents a function?
Dafna11 [192]
The 3 option
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3 0
2 years ago
Please help, please
Kisachek [45]

Answer:

Total amount of fencing needed as an algebraic expression in terms of x is: <em>10x</em><em> </em><em>+</em><em> </em><em>3</em> .

Step-by-step explanation:

As it is given that each rectangle has the same dimensions, the dimensions of each rectangle must be: x units by 2x + 1 units.

Based on this, we can calculate the total amount of fencing needed.

Let width of each rectangle = x

Let length of each rectangle = 2x + 1

There are 4 widths and 3 lengths in total of fencing.

Therefore:

= 4 ( x ) + 3 ( 2x + 1 )

Expand:

= 4x + 6x + 3

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7 0
3 years ago
A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend
MA_775_DIABLO [31]

From the diagram above you can see that points A and B have coordinates (8,0) and (-4,6), respectively.

The equation of the line passing through the pointa A and B is:

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y-0=\dfrac{6-0}{-4-8}(x-8),\\ \\y=-\dfrac{6}{12}(x-8),\\ \\y=-\dfrac{1}{2}(x-8),\\ \\y=-\dfrac{1}{2}x+4.

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8 0
3 years ago
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