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mojhsa [17]
2 years ago
6

Find the smallest number such that

Mathematics
2 answers:
dedylja [7]2 years ago
5 0

Answer:

I think the answer is 7

don't blame me if I'm wrong

Elis [28]2 years ago
4 0

Answer:

359

Step-by-step explanation:

the prime factors of the numbers are

18 = 2×3×3

20 = 2×2×5

24 = 2×2×2×3

the lowest common multiple is therefore

2×2×2×3×3×5 = 360

the difference between the checked divisor numbers and the expected remainder is constantly 1 :

18 - 17 = 1

20 - 19 = 1

24 - 23 = 1

so, we can deduct this constant 1 from the LCM and get the desired number :

360 - 1 = 359

verify :

359 ÷ 18 = 19 remainder 17

359 ÷ 20 = 17 remainder 19

359 ÷ 24 = 14 remainder 23

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What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest
maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

                                                      A_{B} =lb.....................(3)

              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

                                                            = (10)(2)

                                                            = 20

                                    Area of B, A_{B} = 20 cm^{2}

Step:4

               From the equation (1),

                               Area of given diagram = 20+ 9.81747

                                                            Area = 29.817 square centimeters

Result:

            The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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