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Answer:
The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile
This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.




The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
First calculate the distance covered going down:
d_down = (16 m / s) * 8 s = 128 m
Then the distance going up is:
d_up = 71 m
So the distance from the ledge to the nest is:
d = 128 m – 71 m = 57 m
Therefore the elevation is:
<span>elevation = 1364 m + 57 m = 1421 m</span>
Answer:

Step-by-step explanation:
The equation is

Solve for x
we know that

substitute

so
