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OLga [1]
2 years ago
11

Solve 13/19-(-1/19) a.-12/19 b.-14/19 c.14/19 d.12/19

Mathematics
2 answers:
mojhsa [17]2 years ago
7 0

Answer:

C

Any time you have a subtraction and a negitive right next to eachother, it means to add. So, you would add 13 and 1 to get 14, then keep the denominator 19 to get 14/19.

Step-by-step explanation:

irina [24]2 years ago
6 0

Answer: 14/19

To subtract fractions, we want to find the LCD and then combine. So the correct answer is C) 14/19

<h3><u>Exact Form:</u></h3>

14/19

<u>Decimal Form:</u>

0.73684210

<em>Hope this helps =)</em>

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Brian borrowed a 20 foot extension ladder to use when he paints hes house. If he sets the base of the ladder 6 feet from the hou
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48. Reading Rates The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute a
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Answer:

The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 125, \sigma = 24

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile

This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 125}{24}

X - 125 = 1.28*24

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The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.

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Answer:

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Step-by-step explanation:

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