Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
The answer is -s^1000+s^22+s^220+1.
Which questions. There is no pic
1) Data:
Meal calories consumed
Breakfast 400 cal
Lunch 350 cal
Dinner x
------------------
Total 400 + 350 + x = 750 + x
2) Equation: <span>
She consumes 2/3 of her daily calories at dinner => (2/3)[750+x] = x
3) Analyze each statement:
</span><span>a) Lena
consumed 1500 cal at dinner.
Solve the equation to find if the statement is true:
</span>
<span><span>(2/3)[750+x] = x</span>
2(750+x) = 3x
1500 + 2x = 3x
1500 = 3x - 2x
x = 1500
Conclusión: TRUE stament.
b) Do you equation 2/3 (x+400+350)=x can be
used to model the situation.
That is the same equation that I found above.
Conclusion: TRUE statement
c) Lena consumed 500 cal at dinner.
She consumed (2/3) * 1500 = 500 cal
Conclusion: TRUE statement
d) Lena
consumed 1000 cal at dinner.
No, we calculated that she consumed 500 cal at dinner.
Conclusion: FALSE statement
e) The equation 2/3(x)=x(400+350) can be used
to model the situation.
No: (2/3) x = 500 and x(400+350) = 500*750 = 375,00, which are not equal.
Conclusion: FALSE statement.
f) The equation 2/3x(400+350)=x Can’t be used to
model the situation
No: in that equation the variable x cancels out because it appears a factor at both sides.
</span>Conclusion: TRUE statement
Answer:
Step-by-step explanation:
Aug
15 = 1 26 = 23.04 Total $737.28 that's a great deal
16 = 2 27 = 46.08
17 = 4 28 = 92.16
18 = 8 29 = 184.32
19 = 16 30 = 368.64
20 = 36 31 = 737.28
21 = 72
22 = 1.44
23 = 2.88
24 = 5.76
25 = 11.52
