Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
You will save $522 by paying cash. 165*24=3960 3960-3438=522
:)
Answer:
sec(theta)=1/cos(theta)
Step-by-step explanation:
sec(theta)=1/cos(theta)
I’m pretty sure a, d, e and f are correct :)
The GCF of -42, 21, 84 is 21
21 x 1 = 21
21 x 2 = 42
21 x 4 = 84
hope i helped
