Which values should you plot to show a linear relationship?

Mathematics

1 answer:

konstantin123 [22]2 years ago

7 0

The values that show a linear relationship is "Day" on the x-axis and "number of seeds" on the y-axis.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard form of a linear equation is given by:

y = mx + b

Where m is the slope of the line and b is the y intercept.

The values that show a linear relationship is "Day" on the x-axis and "number of seeds" on the y-axis.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

You might be interested in

Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle.

sashaice [31]

5x^2 + 5y^2 + 10x − y = 0 it is the same of 
x^2 + y^2 + 2x −1/5y = 0
and then 
(x + 1)^2 - 1+ (y−1/10)^2 -1/100=0
 (x + 1)^2 + (y −1/10)^2 =(101/100)

the center is C(-1, 1/10), and the radius is R= sqrt(101)/10

4 0

3 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.