Ask question

Ask question

All categories

3 years ago

10

a cook needs 12 pounds of flour he wants to spend the least amount of money if a 2 pound bag costs $1.59 and a 5 pound bag costs

$2.89 how many bags of each type of flour should he buy what will be the total cost

2 answers:

Virty [35]3 years ago

4 0

He should buy two 5 pound bags and one 2 pound bag.

Anna [14]3 years ago

4 0

Two five pound bags one two pound

You might be interested in

There is strong believe that language skills of Political science students are greater than students who study Finance. Research

BaLLatris [955]

Answer:

a

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 > \mu_2$

b

$p-value = 0.232$

c

The decision rule is

Fail to reject the null hypothesis

Step-by-step explanation:

From the question we are told that

The value given is

S/N

1 7 5

2 4 3

3 8 7

4 8 8

5 7 9

6 7 5

7 6 5

Generally the sample mean for the first sample is mathematically represented as

$\= x _1 = \frac{\sum x_i }{n}$

=> $\= x _1 = \frac{7 +4 + \cdots + 6}{7}$

=> $\= x _1 = 6.714$

Generally the sample mean for the second sample is mathematically represented as

$\= x _2 = \frac{\sum x_i }{n}$

=> $\= x _2 = \frac{5 + 3+ \cdots + 5}{7}$

=> $\= x _2 = 6$

Generally the sample standard deviation for the first sample is mathematically represented as

$s_1 = \sqrt{\frac{\sum (x_i - \= x_1)^2 }{n-1 } }$

=> $s_1 = \sqrt{\frac{ (7 - 6.714 )^2 +(4 - 6.714 )^2 + \cdots + (6 - 6.714 )^2 }{7-1 } }$

=> $s_1 = 1.905$

Generally the sample standard deviation for the second sample is mathematically represented as

$s_2 = \sqrt{\frac{\sum (x_i - \= x_2)^2 }{n-1 } }$

=> $s_2 = \sqrt{\frac{ (5 - 6.714 )^2 +(3 - 6.714 )^2 + \cdots + (5 - 6.714 )^2 }{7-1 } }$

=> $s_1 = 4.33$

Generally the pooled standard deviation is

$s = \sqrt{\frac{(n_1 - 1 )s_1^2 + (n_2 - 1 )s_2^2}{n_1 + n_2 -2 } }$

=> $s = \sqrt{\frac{(7 - 1 )1.905^2 + (7 - 1 )4.333^2}{7 + 7 -2 } }$

=> $s = 1.766$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x _1 - \= x_2 }{s * \sqrt{\frac{1}{n_1} + \frac{1}{n_2}} }$

=> $t = \frac{6.714 - 6 }{1.766 * \sqrt{\frac{1}{7} + \frac{1}{7}} }$

=> $t = 0.757$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 - 2$

=> $df = 7 + 7 - 2$

=> $df = 12$

From the t distribution table the probability of $t = 0.757$ at a degree of freedom of $df = 12$ is

$t_{ 0.757 , 12} = 0.232$

Generally the p-value is

$p-value = t_{ 0.757 , 12} = 0.232$

From the values obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

8 0

3 years ago

Determine the range of the function.

Naya [18.7K]

Answer:

$Solution: f(x)\ge-5\\Interval:[-5,\infty)$

Step-by-step explanation:

Equation: $\frac{1}{4} x^2-5 = y$

1). $\frac{1}{4} x^2-5 = y$ → $\frac{x^2}{4}-5=y$

2). $\frac{x^2}{4}-5=y$ ∴ $a=\frac{1}{4}, b=0, c=-5$

3). $x_v=-\frac{b}{2a}$

$=-\frac{0}{2(\frac{1}{4})}$

$=0$

4). now plug $x_v$ into $y_v$

$y_v=\frac{0^2}{4}-5$

$=-5$

5). Minimum (0,-5) ∴ $f(x)\ge-5$

4 0

3 years ago

I’ll gift u a milf if you answer

Sveta_85 [38]

Answer:

$x = - \frac{11}{2}$

divide each term by two and simplify.

Give me my milf.

8 0

3 years ago

UURGENTTT PLLZ HELP WILL MARK AS BRANLIEST!!!

lapo4ka [179]

Answer:

Surface area of the wood to be painted = ( $r^{2}$ + r $\sqrt{h^{2} + r^{2} }$ ) $\pi$ - 16 $\pi$

Step-by-step explanation:

Surface area of a cone is given as the sum of the surface area and the area of its base.

i.e Surface area = $\pi$ $r^{2}$ + $\pi$ Lr

where: L is the length of its slant height and r is the radius.

Applying the Pythagoras theorem,

L = $\sqrt{h^{2} + r^{2} }$

Thus,

Surface area = $\pi$ r (r + $\sqrt{h^{2} + r^{2} }$ )

The given cylindrical hole has a radius of 4 cm and depth 2 cm.

The area of one of its circular surfaces = $\pi$ $r^{2}$

= $\pi$ × $(4)^{2}$

= 16 $\pi$ $cm^{2}$

The surface area of the piece of wood to be painted = surface area of cone - area of cylindrical circular surface.

Surface area of the wood to be painted = $\pi$ r (r + $\sqrt{h^{2} + r^{2} }$ ) - 16 $\pi$

7 0

3 years ago

Are these right triangles ?<br> Answer please ASAP

V125BC [204]

Answer: Yes.

Step-by-step explanation: Right triangles are 90° and with a square. This is a right triangle. Just remove the line that makes it a triangle, you'll see.

4 0

3 years ago