Answer:
3×10^4
Step-by-step explanation:
The desired factor is found by calculating the ratio of the two numbers:
k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4
The first number is 3×10^4 = 30,000 times as much as the second number.
To find the sale price multiply the original cost by the sale percentage. (37x.2= 7.4) subtract this discount from the total (37-7.4= 29.6) this is your sale price. Now multiply this by the other percentage (29.6x.15= 4.44) (29.6-4.44= 25.16) $25.16 is your final answer
Answer:
translate (x,y) (x-5,y+8)
I'm not sure if it only wants you to find Equation 1 or go further and solve:
x = the number of 5c coins
y = the number of 10c coins
Equation 1: the total number of coins is 65
x + y = 65
total value of $3.80
0.05x + 0.1y = 3.8
<u>Simultaneous Equations</u>
Make one coefficient the same
10 * (0.05x + 0.1y = 3.80 = 0.5x + y = 38
x + y = 65
0.5x + y = 38
Subtract the equations
(x + y) - (0.5x + y)= 65 - 38
(x - 0.5x) + (y - y) = 65 - 38
0.5x = 27
x = 54
Substitute it into the original equation to find y.
x + y = 65
54 + y = 56
y = 65 - 54 = 11
Substitute it into the other equation to check it's right.
0.05x + 0.1y = 3.8
0.05(54) + 0.1(65) = 3.8
x = 54 5c coins
y = 11 10c coins
Answer:
Step-by-step explanation:
The domain of all polynomials is all real numbers. To find the range, let's solve that quadratic for its vertex. We will do this by completing the square. To begin, set the quadratic equal to 0 and then move the -10 over by addition. The first rule is that the leading coefficient has to be a 1; ours is a 2 so we factor it out. That gives us:

The second rule is to take half the linear term, square it, and add it to both sides. Our linear term is 2 (from the -2x). Half of 2 is 1, and 1 squared is 1. So we add 1 into the parenthesis on the left. BUT we cannot ignore the 2 sitting out front of the parenthesis. It is a multiplier. That means that we didn't just add in a 1, we added in a 2 * 1 = 2. So we add 2 to the right as well, giving us now:

The reason we complete the square (other than as a means of factoring) is to get a quadratic into vertex form. Completing the square gives us a perfect square binomial on the left.
and on the right we will just add 10 and 2:

Now we move the 12 back over by subtracting and set the quadratic back to equal y:

From this vertex form we can see that the vertex of the parabola sits at (1,-12). This tells us that the absolute lowest point of the parabola (since it is positive it opens upwards) is -12. Therefore, the range is R={y|y ≥ -12}