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madam [21]
2 years ago
7

HELP

Mathematics
1 answer:
Ket [755]2 years ago
5 0

Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.

<h3>How can the duration of signal reception be found?</h3>

Radius of broadcast of the transmitter = 50 miles

Location of starting point = 56 miles north of the transmitter

Location of destination city = 58 miles east of the transmitter

Therefore we have;

Slope of the line joining the two cities

= 56 ÷ (-58) = -0.966

Which gives the equation of the line as follows;

y = -0.966•x + 56

The equation of the circle is;

{x}^{2}  +  {y}^{2}  =  {50}^{2}

{x}^{2}  +  { ( - 0.966x + 56)}^{2}  =  {50}^{2}

1.933156•x^2 - 108.192•x + 636 = 0

Which gives;

  • x = 6.67 or x = 49.29

Therefore;

When x = 6.67, we have;

  • y = -0.966 × 6.67 + 56 = 49.56

When x = 49.29, we have;

  • y = -0.966 × 49.29 + 56 = 8.4

The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;

l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>

  • The length of the drive during which the signal is received is 59.24 miles

Learn more about the equation of a circle here:

brainly.com/question/502872

#SPJ1

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