The area of any triangle is (1/2) x (length of the base) x (height) .
In this problem, we know the triangle's height,
but what is the length of the base ?
The base is the side that the triangle is sitting on. This particular triangle
is an equilateral one, and its perimeter is 60m. So each side must be 20m.
No matter which side the triangle is sitting on, the length of the base is 20m.
Area = (1/2) x (base) x (height)
Area = (1/2) x (20m) x (17.3m) = <em>173 m²</em>
Answer
-64
just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64
Answer:
x=2
Step-by-step explanation:
y=3x+2
y=x+6
Since you're stating that, they both equal because equation is equated to equation 2 because of the Y.
Therefore, substitute into both equations as shown:
3x+2=x+6
3x-x=6-2 (bring 2 to the other side by subtracting 2 as well as x)
2x=4
2x/2=4/2 (dividing 2 on both sides to get rid off 2 in 2x)
x=2.
Answer: Length of AB is 16 cm
Step-by-step explanation:
Given: Diameter of a circle is 20 cm and CE = 4 cm
Now as shown in figure AO, BO, CO are radii
Therefore
AO=BO=CO= 10 cm
Now
Now in Δ OEB
∠OEB =90°
Therefore by Pythagoras theorem : In a right angle triangle the square of hypotenuse is equal to the sum of square of other two sides.
So we have
Now as we know perpendicular to the chord from the center of a circle bisect the chord.
Therefore
Hence , the length of AB is 16 cm .
