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allsm [11]
3 years ago
8

OK yall i need help with this.I honestly hate geometry.Seriously.I need good student with good explanation skills.Ill mark brain

lest and up my points!​

Mathematics
1 answer:
jonny [76]3 years ago
3 0

Answer:

Step-by-step explanation:

In parallelogram, opposite sides are parallel and equal

3x + 7 = 5x -17  

3x - 5x = -17 - 7

-2x = - 24

x = -24 /-2

x = 12        

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What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)
Nataly_w [17]

Answer:

Given that an article suggests

that a Poisson process can be used to represent the occurrence of

structural loads over time. Suppose the mean time between occurrences of

loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a

4-year period? c). How long must a time period be so that the probability of no loads

occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a

4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads

occurring during that period is at most 0.3 is given by: 3.3 years

Step-by-step explanation:

8 0
3 years ago
A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate
yulyashka [42]

Answer:

25

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)

C'(x) = (-\dfrac{12500}{x^2})  + 20  --- (2)

At C'(x) = 0

\dfrac{12500}{x^2} = 20

\dfrac{12500}{20} = x^2

x^2= 625

x = \sqrt{625}

x = 25

C'' (x) = -12500 \times \dfrac{-2}{x^3} +0

C'' (x) = \dfrac{25000}{x^3}

where; x = 25

C'' (x) = \dfrac{25000}{25^3}

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

4 0
3 years ago
A jar contains five red marbles and three green marbles. A marble is drawn at random and not
Alex787 [66]
5+3=8
Every time you draw, its minus one from denominator

1st marble red: 5/8

2nd marble green: 3/7
5 0
3 years ago
Solve 3[-x+(2x+1)]=x-1
12345 [234]

Answer:

x = 1

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ÷)

3 0
3 years ago
Multiply 3xyz ^ 2 / 6y ^ 4 by 2y / x z ^ 4
Marat540 [252]

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8 0
3 years ago
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