Let's start by finding a common denominator for all of these fractions. In this case, we will use 60.
3/4 = 45/60
2/3 = 40/60
3/5 = 36/60
7/10 = 42/60
13/20 = 39/60
The closest to 45/60 is 42/60/ Therefore, 7/10 is the closest to 3/4
Answer:
F(-3)=12
F(2)=7
F(0)=3
F(5)=28
Step-by-step explanation:
Y=-2x-8+2
y=-2x-6
if x=0;Y=-6
IF y=0;x=-3
to plot the graph; plot point in -6 y-axis and -3 on the x-axis join them together then extend the line
hope u understood
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
$8.25
Step-by-step explanation:
1.25+(2.25x2)+1.00+(1.25x2)=8.25
