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1 year ago

Paulo is flying a kite as shownin the right. Find the length of the kite string.

Mathematics

1 answer:

mixas84 [53]1 year ago

8 0

The length of the kite string is 50 ft

<h3>How to determine the length of the kite string?</h3>

The string and the kite form a right triangle.

So, the length can be calculated using Pythagoras theorem as follows:

c^2 = 30^2 + 40^2

This gives

c^2 = 2500

Take the square roots

c = 50

Hence, the length of the kite string is 50 ft

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Rama09 [41]

Answer:

Option B. 3/4 > 2/3 is the correct answer.

Step-by-step explanation:

Lets look at the options one by one

A. 1/2 < 1/3

This inequality converts into 0.5<0.33 which is false.

B. 3/4 > 2/3

This simplifies to 0.75>0.666 which is true.

C. -1/4 < - 2/3

This converts to -0.25<-0.666 which makes the inequality false.

D. -1 > 3/4

This converts to -1>0.75 which makes the inequality false.

Hence,

Option B. 3/4 > 2/3 is the correct answer.

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3 years ago

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zlopas [31]

Step-by-step explanation:

transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

0 = ln (x - 4)

$e^{0} = e^{ln (x - 4)}$

1 = x - 4

+4 +4

5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

1 = ln (x - 4)

$e^{1} = e^{ln (x - 4)}$

e = x - 4

+4 +4

e + 4 = x

6.72 = x

(6.72, 1)

Domain: x - 4 > 0

+4 +4

x > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

= - 3⁰⁺⁵

= - 3⁵

= -243

Horizontal Asymptote: y = 0 (explanation above)