The value of x is 3 given that ST = 8x + 11 and TU = 12x-1
The point that bisects a line divides the line into two equal parts
If T is the midpoint of SU, the following are true:
Given the following
ST = 8x + 11
TU = 12x-1
Since ST = TU
8x+11 = 12x-1
8x - 12x = -1 - 11
-4x = -12
x = 12/4
x = 3
Hence the value of x is 3 given that ST = 8x + 11 and TU = 12x-1
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The correct answe would be 4 all functions are at the same rate
There is no sum for this geometric series. it diverges rather than converges due to the absolute value of the common ratio (r), which is -3, being 3. for a geometric series to have a sum (to converge), the absolute value of r must be less than 1.
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
Answer:
Use L x W x H
Step-by-step explanation:
So...
5 x 12 x 8 = 480
