How do I delete my question?
1 answer:
You might be interested in
Answer:
Option A is correct
The function has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
Answer: (a) -7 (b) (c)
(d) 4
Step-by-step explanation:
A) f(x) = 2x - 3 when x is between -5 and -2 (including -5 and -2)
B) f(x) = x² when x is between -2 and 2 (including 2)
C) when x is between 2 and 5 (including 5)
a) Equation A includes x = -2
f(x) = 2x - 3
f(-2) = 2(-2) - 3
= -4 - 3
= -7
b) Equation B includes x =
f(x) = x²
c) Equation C includes x = 4
d) Try each equation to see if x falls within the values given.
A) f(x) = 2x - 3
-2.5 = 2x - 3
0.5 = 2x
0.25 = x NOT VALID since x should be between -5 and -2
B) f(x) = x²
-2.5 = x²
NOT VALID since x cannot be an imaginary number
C)
VALID since x is between 2 and 5