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N76 [4]
3 years ago
6

Which of the following sets of numbers could represent the three sides of a right

Mathematics
2 answers:
Kamila [148]3 years ago
8 0
The answer is either the first or second if u can put 2 down then both
klemol [59]3 years ago
7 0

Answer:

A,B

Step-by-step explanation:

sum of angles of a right angle triangle is 90 meaning the will either be 90 or less and both of them certify this law.

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You can drive your car 21.7 miles with one gallon of gasoline. At that rate, how many miles can you drive with 13.2 gallons of g
Phantasy [73]

Answer:

286.44 miles........

3 0
3 years ago
Divide 28 bottles of water into two groups so the ratio is 3 to 4. Be sure to show your work.
tatyana61 [14]

Answer:

12:16

Step-by-step explanation:

28 split into two groups could be 12 : 16. To check the work, see if 3/4 is equal to 12/16. It is, so this is the accurate ratio, as 12 + 16 = 28 and 12/16 = 3:4.

4 0
2 years ago
17. What expression is equivalent to log(200) - log (2)? Calculate the answer.
IRINA_888 [86]

Answer: 2

Step-by-step explanation:

Recall from the laws of Logarithms:

Log a - Log b = Log ( a/b )

That means

Log 200 - Log 2 = Log ( 200/2)

= Log 100 , which could be written as

Log 10^{2}

Recall from laws of Logarithms:

Log a^{b} = b Log a

Therefore:

Log10^{2} = 2 Log 10

Also from law of Logarithm

Log 10 = 1

Therefore 2 Log 10 = 2 x 1

= 2

3 0
2 years ago
(9x−2.25)=(1.6+9x)<br><br> help
mel-nik [20]
Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.
4 0
3 years ago
Help please!! How do I solve this
egoroff_w [7]
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
 2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0  We will replace expression ( 2 on x) with variable t => 2 on x=t  =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 =>     t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 =>                   2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution. 
Check 2:   2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 => 
1-5+4=0 => 0=0  Identity provin solution.
5 0
3 years ago
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