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2 years ago

A student survey his classmates to determine their favorite movies

Mathematics

1 answer:

zheka24 [161]2 years ago

3 0

Answer:

The answer is C. Hope it helps

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Add.<br> (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)<br> express the answer in standard form.

Alex777 [14]

$(-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)\\\\=-x^3+26x^2-7-13+6x^4-x^3+8x+27\\\\=6x^4+(-x^3-x^3)+26x^2+8x+(27-7-13)\\\\=\boxed{6x^4-2x^3+26x^2+8x+7}$

4 0

3 years ago

PLEASE HELP I GIVE 29 POINTS TO WHOEVER GETS THIS RIGHT

-Dominant- [34]

Direction: Isolate the variable by dividing each side by factors that don't contain the variable.

Here are the answers for all 15 questions:

1) x < - 2

2) x < 4

3) x > - 15/7

4) y < 28/5

5) x > 6

6) y > - 10/9

7) 0 < 333

8) x > 2

9) x > - 10

10) y > - 3

11) y > - 4

12) x > 3

13) x < 9/8

14) x > - 2

15) h < 7/2

4 0

2 years ago

Read 2 more answers

A new amusement park presold discounted tickets for the opening day as well as upon arrival at the park the opening day ticket s

julia-pushkina [17]

Answer:

-64 tickets per hour

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p

SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

$\frac{c}{a} = 1\\=> \frac{p - 4}{4} = 1\\=> p - 4 = 4\\=> p = 4 + 4 = 8$

5 0

4 years ago

Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)

Paladinen [302]

Step-by-step explanation:

Let x represent theta.

$\sin( \frac{\pi}{4} - x )$

Using the angle addition trig formula,

$\sin(x - y) = \sin(x) \cos(y) - \cos(x) \sin(y)$

$\sin( \frac{\pi}{4} ) \cos(x) - \cos( \frac{\pi}{4} ) \sin(x)$

$( \frac{ \sqrt{2} }{2}) \cos(x) - (\frac{ \sqrt{2} }{2} )\sin(x)$

Multiply one side at a time

Replace theta with x , the answer is

$\frac{ \sqrt{2} \cos(x) }{2} - \frac{ \sin(x) \sqrt{2} }{2}$

2. Convert 30 degrees into radian

$\frac{30}{1} \times \frac{\pi}{180} = \frac{\pi}{6}$

Using tangent formula,

$\tan(x + y) = \frac{ \tan(x) + \tan(y) }{1 - \tan(x) \tan(y) }$

$\frac{ \tan(x) + \tan( \frac{\pi}{6} ) }{1 - \tan(x) \tan( \frac{\pi}{6} ) }$

Tan if pi/6 is sqr root of 3/3

$\frac{ \tan(x) + ( \frac{ \sqrt{3} }{3} ) }{1 - \tan(x) (\frac{ \sqrt{3} }{3} ) }$

Since my phone about to die if you later simplify that,

you'll get

$\frac{(3 \tan(x) + \sqrt{3} )(3 + \sqrt{3} \tan(x) }{3(3 - \tan {}^{2} (x) }$

Replace theta with X.

4 0

3 years ago