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2 years ago

13

I would ask a question but half the mfkas on here have failed me so many tests. So I j want to let you guys know that you all ar

e r e t a r t e d.

1 answer:

DedPeter [7]2 years ago

7 0

Answer:

please dont use the r slur :)) and if you care so much about your grades, heres an idea!! study on your OWN and dont rely on others

Step-by-step explanation:

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Two classes are planning to go on a field trip together. One clas with 18 students is being joined by 6 boys and 11 girls from a

Serjik [45]

Answer: The boys made up 6b of the original class.

Step-by-step explanation:

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3 years ago

What is the LCD of 3/10 and -4/15??

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The LCD is 30. The fractions would be 9/30 and -8/30

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3 years ago

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The zoo needs to replace some of the railroad tracks that support their train ride. The total length of the track is 500 feet,

Darya [45]

Answer:

293 feet.

Step-by-step explanation:

Their track is 500 feet, and there are three sections. Add these sections(61+83+63=207) and subtract from the total(500-207=293)

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2 years ago

Which equation demonstrates the additive identity property?

Alik [6]

Answer:

The second one

Step-by-step explanation:

Additive identity is adding 0 to a number

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2 years ago

Match the following items.

max2010maxim [7]

Answer:

1. ∠ABD = 20°.

2. Arc AB = 140°.

3. Arc AD = 40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

$\angle DAB=90^{\circ}$

Using angle sum of property in triangle ADB we get,

$\angle ADB+\angle DAB+\angle ABD=180^{\circ}$

$70^{\circ}+90^{\circ}+\angle ABD=180^{\circ}$

$\angle ABD=20^{\circ}$ .

Draw a line segment AO.

In triangle AOD, AO=OD, so

$\angle ODB=\angle OAD=70^{\circ}$

Using angle sum property in triangle AOD,

$\angle AOD+\angle ODA+\angle OAD=180^{\circ}$

$\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}$

$\angle AOD=40^{\circ}$

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

$\angle AOD+\angle AOB=180^{\circ}$

$40^{\circ}+\angle AOB=180^{\circ}$

$\angle AOB=140^{\circ}$

Therefore length of arc AB is 140°.

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3 years ago