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muminat
4 years ago
7

Which inequality matches the graph?

Mathematics
2 answers:
inn [45]4 years ago
8 0

Answer:

D) x ≤ -2

Step-by-step explanation:

The dot is at -2 = -2

the dot is filled in = ≤ or ≥ because its means equal too

think of ≤ or ≥ like arrows = it points left.  

so its x ≤ -2


<em>Note on using the  ≤ or ≥  like pointing arrows</em>

this only works if its written:

variable <   constant form,

which is the way they are usually seen, like x < 5

but it could be 5 > x which means the > points the opposite way

nata0808 [166]4 years ago
3 0

<u><em>Hello! :)</em></u>

<u><em>Answer:</em></u>

<u><em>D. x≤-2</em></u>

<u><em>*The answer must have a negative sign and less than or equal to.*</em></u>

Step-by-step explanation:

Lesson: It's about the graphing inequalities

An inequality is a statement that compares mathematical expressions that are not equal. The expressions are separated by an inequality symbol (<,>, ≤, ≥, or ≠).

The arrow points to the left. The circle is closed.

Hope this helps!

Have a nice day! :)

:D

-Charlie

Thanks!

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In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, &amp; KM = 3x + 23, find x &amp; the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

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3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

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    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

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