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2 years ago

100000/222solve with proper steps and find the remainder

Mathematics

1 answer:

Mrac [35]2 years ago

5 0

Answer: 450 rest 100

Step-by-step explanation:

So, we need to calculate this division 100.000/222 and get the rest.

Well, 222 enters in 1000 by 4 times.

222 times 4 is 888

So, 100.000/222 = 4

888-

We subtract 888 from 1000.

That will be 112

100.000/222 = 4

888

112

Now, get the next 0 down next to 112

100.000/222 = 4

888

1120

222 get in 1120 by 5 times.

5 times 222 = 1110

divide 1120 by 1110

100.000/222 = 45

888

1120

1110

That will be 10

100.000/222 = 45

888

1120

==10

Get the next zero down

100.000/222 = 45

888

1120

==100

222 gets in 100 by 0 times.

100.000/222 = 450

888

1120

==100

100 subtracted by 0 is 100

100.000/222 = 450

888

1120

==100

100

The rest is 100 and the result is 450

Now, you can do the verification:

222 time 450 is 99,900.

If you add the rest to 99,900 it will be 100.000. So the result is good

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A biologist is researching a newly-discovered species of bacteria. At time t = 0 hours, she puts one hundred bacteria into what

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Answer:

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Step-by-step explanation:

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3 years ago

Given the functions below, find (f - g) (2).<br> f(x)<br> x2 + 3<br> g(x) = 4x – 3<br> =

kakasveta [241]

Answer:

(f - g)(2) = 2

Step-by-step explanation:

Given the functions below, find (f - g) (2).

f(x) = x² + 3

g(x) = 4x – 3

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5 0

2 years ago

Find x in this porportion 5/2x =25/4

Andrei [34K]

Answer:

x = $\frac{2}{5}$

Step-by-step explanation:

Given

$\frac{5}{2x}$ = $\frac{25}{4}$ ( cross- multiply )

25 × 2x = 5 × 4

50x = 20 ( divide both sides by 50 )

x = $\frac{20}{50}$ = $\frac{2}{5}$

6 0

3 years ago

Read 2 more answers

A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin

sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

$P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}$

The probability that they each win six games is k=6.

$P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}$

$P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625$

$P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625$

$P(X=6)=0.225$

Therefore, The probability that they each win six games is 0.225.

3 0

3 years ago

HELP ASAP Three generous friends, each with some cash, redistribute their money as follows: Ami gives enough money to Jan and To

DENIUS [597]

Answer:

$252

Step-by-step explanation:

This is quite a neat question, with no fixed equation. Given that each person gives the other two enough money to double their cash, if Toy had 36 dollars beginning, and 36 at the end - presumably the cash of each person, ( their starting and original ) should be the same as well. Respectively each should be a multiple of 36 dollars.

Jan's " give away " = Ami + 36, Jan - 108, Toy + 72

Toy's " give away " = Ami + 72, Jan + 36, Toy - 108

Therefore, we can conclude that Ami = 144 at the start, presuming he gave away 108 dollars, with a remaining 36. Jan, having 144 dollars ( after having his 72 dollars doubled by Ami ) gives 36 to Ami to double his amount, and 72 to double Toy's doubled amount, remaining with 36 dollars. Now Ami has 72 dollars, Jan has 36, and Toy has 144. Then, Toy double's Ami and Jan's amount, giving away 72 and 36 dollars, remaining with 36 dollars himself. Therefore, Ami has 144 dollars, Jan has 72 dollars, and Toy has 36 dollars both at the beginning and end.

144 + 72 + 36 = 252 dollars ( in total )

6 0

3 years ago

100000/222solve with proper steps and find the remainder​

100000/222solve with proper steps and find the remainder