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2 years ago

List these fractions fromleast to greatest 3/8 5/8 4/8 2/8 7/8

Mathematics

1 answer:

melomori [17]2 years ago

8 0

Answer: 2/8, 3/8, 4/8, 5/8, 7/8

Step-by-step explanation:

Since they all have a common denominator, we can list them based on their numerator without having to worry about the denominator.

2/8 < 3/8 < 4/8 < 5/8 < 7/8

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If you run a marathon of 26 1/5 miles in a time of 5 4/5 how far do you run in 1 hour<br><br>pls

alisha [4.7K]

First let's make both the miles and the hours ran improper fractions:

$26+\frac{1}{5}=\frac{131}{5}\\ 5+\frac{4}{5}=\frac{29}{5}$

So, to find our miles per hour, we have to divide the miles by the hours to get: $\frac{\frac{131}{5}\text{miles}}{\frac{29}{5}\text{hours}}=\frac{131\text{miles}}{29\text{hours}} \\ \text{ Now we have to divide the top and the bottom by 29 to get our miles per hour so: }\\ \frac{\frac{131}{29}}{\text{hour}} \approx \frac{4.52 \text{miles}}{\text{hour}}$

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3 years ago

(7x10*5)x(3x10*2) in standerd form

marishachu [46]

Answer:

21,000

Step-by-step explanation:

This is more of straightforward multiplication, so I cannot explain much! If you want me to try to do more, then just comment.

(7 * 10 * 5) * (3 * 10 * 2)

= (70 * 5) * (30 * 2)

= (350) * (60)

= 21,000

Thusly, in standard form, the equation given is $\boxed{21,000}$ .

Hope this helps! (:

7 0

3 years ago

Which math function describes the following situation?

MissTica

This is the concept of inequality;
We are told that the distance a car travels depends on how full gas tank is, this means that the car will travel until the point when gasoline is finished. Thus,
This mean that if the if the distance is given by the function f(x), x will be the gasoline since it is the dependent variable, liters this in other words can be written as (if the tank holds 89 ):

f(x)=distance(gasoline)<89

thus the correct answer will be:

B] Distance (amount of gasoline) < 89

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3 years ago

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faltersainse [42]

Answer: 6

Step-by-step explanation:

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3 years ago

Read 2 more answers

NO LINKS!! Please help me with these graphs. Part 1

AveGali [126]

Problem 9

The instructions aren't stated anywhere, but I'm assuming your teacher wants you to find the equation of each parabola.

The vertex here is (h,k) = (-6,-4) which you have correctly determined.

This means

$y = a(x-h)^2 + k\\\\y = a(x-(-6))^2 +(-4)\\\\y = a(x+6)^2 - 4\\\\$

Next we plug in one of the other points on the parabola. We cannot pick the vertex again. Let's pick the point (-4,0) which is one of the x intercepts. We'll do this to solve for 'a'

$y = a(x+6)^2 - 4\\\\0 = a(-4+6)^2 - 4\\\\0 = a(2)^2 - 4\\\\0 = a(4) - 4\\\\0 = 4a-4\\\\4a-4 = 0\\\\4a = 4\\\\a = 4/4\\\\a = 1\\\\$