1. 3x - 4y = 20
2. x - 3y = -6
x should equal -2 and y should equal -3 to solve this i multiplied the first equation by 2 then got rid of the 4y and -4y then i added the 14x to the 9 equaling 23x and added the -40 to the -6 which became 23x=-46 i solved this getting -s for x, then i plugged that into the equations to get y which was -3
Answer:
(x, y) = (-2, -3)
WORK:
2x + 4y = -16 =
-2x + 2y = -2 =
(^ the two’s cancel out) =
6y = -18 =
(^ you need to divide 6 on both sides to get just y) =
6y/6 = -18/6 =
(^ the six’s cancel out) =
y = -3 =
(^ now you have to plug this in to get x) =
2x + 4(-3) = -16 =
2x - 12 = -16 =
(^ you need to add 12 on both sides to get rid of it on the left side to add it to -16 on the right side) =
2x = -4 =
2x/2 = -4/2 =
(^ now you divide 2 on both sides again to get just y, and they will cancel out) =
x = -2 =
THEREFORE YOU GET (-2, -3)
Well sir according to my calculations if you have a 3 and than you add 3 to the 3 you already have then you would end up with the exact answer of number 6
