A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Step-by-step explanation:
4(3x-2) + 6x(2-1)
10x + 11x
21x
Equating the two formulas for f, you have
n/12 = f = 3y
Then multiplying by 12 you get
n = 36y
This formula converts yards (y) to inches (n).
83-8 =75
Therefore, 75 =b
Answer:
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