Answer:
B
Step-by-step explanation:
Rotating 120
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Answer:
33 • (x + 4)
-----------------
10
Step-by-step explanation:
(1): "3.3" was replaced by "(33/10)".
STEP 1:
33
Simplify ——
10
Equation at the end of step 1:
33
--- • (x + 4)
10
STEP 2:
Final result :
33 • (x + 4)
-----------------
10
I hope I helped, and I always appreciate Brainliest!!! :)
Assuming these are two six-sided dice, you'll have 36 total combinations to test out. To get the 36, I just multiplied the 6 sides on both dice (6x6=36). First you have to test out all the possible combinations. Making it easier for you, I'll just list the ones that work. The combinations that work are 3+6, 4+5, 5+4, and 6+3. This means there are 4 combinations that work out of 36. This gives us the fraction 4/36. Now, this needs to be simplified. Both numbers are divisible by four, so we'll divide by four. The new fraction is 1/9, which is your answer. This means that, statistically speaking, if you rolled those two dice nine times, the sum of the numbers would be 9 only once. You have an 11% chance of having two numbers on the dice that have a sum of 9.
