All categories

2 years ago

Reduce to simplest form - 9/15 + 5/15

Mathematics

2 answers:

Lina20 [59]2 years ago

6 0

4/15 is the answer in simplest form

brilliants [131]2 years ago

5 0

Answer: -4/15

Step-by-step explanation: Since the base denominator is the same, all we have to do is add the numerators (the denominators stay the same.)

-9 + 5 = -4 which is -4/15.

(If my answer was helpful, please mark as Brainliest. I'm trying to get to the Expert rank!)

You might be interested in

7. Look at the picture.

Shtirlitz [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

What are common factors of 18 roses and 30 what do they represent

VashaNatasha [74]

The common factors of the numbers 18 and 30 is 6

<h3>How to determine the common factors of the numbers?</h3>

The numbers are given as

18 and 30

Express 18 and 30 as a product of its factors

So, we have

18 = 2 * 3 * 3

30 = 2 * 3 * 5

Multiply the common factors in the above expression

Common factors = 2 * 3

Evaluate the product

So, we have

Common factors = 6

Hence, the common factors of the numbers 18 and 30 is 6

Read more about common factors at

brainly.com/question/219464

#SPJ1

3 0

1 year ago

There are 252 campers at a summer sports camp. How

Taya2010 [7]

18 teams
Just divide 252 by 14:)

6 0

3 years ago

Read 2 more answers

A full bottle holds 1/4gallon of juice, If of3/5

sineoko [7]

Answer:

1/10 gallon

Step-by-step explanation:

2/5 left of 1/4 gallon

2/5 x 1/4 = 2/20 = 1/10 gallon

6 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

3 years ago