So the formula to find the hypotenuse is:
A²+B²=C²
We can use the bits of information to help us.
The longer leg, A, is 6 more than the shorter leg, B.
This means A=B+6
Let's plug this in.
(b+6)²+b²=C²
The hypotenuse is 6 more than the longer leg. Since we're trying to limit it to one variable, we know that the hypotenuse is 12 longer than the short leg since the long leg is 6 longer than the short leg.
(B+6)²+B²= (B+12)²
Let's multiply.
b²+12b+36+b²=b²+24B+144
2b²+12b+36=B²+24B+144
Let's subtract 12b from both sides.
2B²+36= B²+12B+144
Let's subtract B² from both sides.
B²+36=12B+144
Let's subtract 36 from both sides.
B²=12B+108
Let's subtract 12b from both sides.
B²-12B=108
B=18
The shorter leg is 18 units. The longer leg is 6 more, so 24 units. The hypotenuse is 6 more than the longer leg, so 30.
Shorter leg=18 units
Longer leg= 24 units
Hypotenuse=30 units
First put both in other
24,26,27,30,31,32,32 = 30
29,29,29.5,30,32 =29.5
add them together
=59.5
or if your question is all the numbers together
24,26,27,29.5,29,29,30,30,31,32,32,32= 29+30
= 29.9
The diagram shows statements to prove that both triangles are congruent.
Hence;
Step 1 showed two sides that are congruent for both triangles
Step 2 showed two angles that are congruent
Step 3 showed two sides that are congruent
Therefore, the triangles are congruent by the side-angle-side theorem
Answer:
A good website to use when you need help with this is called desmos.
Step-by-step explanation: