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3 years ago

If M is the Midpoint of AB, then solve for x find the unknown measures the given segments.

Mathematics

1 answer:

Leto [7]3 years ago

8 0

Answer:

If M is midpoint of AB, then

AM=MB

4x-5= 2x+11

2x=16

x=8

AM= 4x-5

=4(8)-5

=32-5

=27

BM=2x+11

=2(8)+11

=16+11

=27

Hope it helps:-)

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480/X - 8 - 480/x = 3

Nataliya [291]

Answer:

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2 years ago

Read 2 more answers

Cole ride his bike for 45 miles at a rate if 15 miles per hour. How long did it take him to ride in 40 miles? PLEASE HELP

tatiyna

15x=45
45/15 =3
X=3
45 miles in 3 hours

How long did it take for 40 miles?

15x=40
40/15 = 2.6666667

15 x 2= 30
15 x 2.5 = 37.5
15 x 2.6 = 39
15 x 2.7 = 40.5
1 hour equals 60 mins

Answer:
It took Cole about 2 hours and 6 mins to ride 40 miles.

5 0

3 years ago

-5(-3x+10)=30 what is x

Feliz [49]

Answer:

5.33333333...

Step-by-step explanation:

it will be like -5 out the bracket x - 3 x which gives you 15 then we'll check again - 5 then you times it by there 10 in the bracket and then it gives you 50 and then it will be there in 15 x - 50 equals to 30 then you take the -50 to the other side where there is 30

then it will be 15 x equals to 30 + 50 and then then 15 x equals to 8 and then you divide both of the sides with 15 then get your answer

-5 (-3x+10)=30

15x-50=30

15x=30+50

15x/15=80/15

x=5.33333...

3 0

3 years ago

You have never seen your favorite superhero in real life. Out of curiosity you calculate her height to be 1.57 mm . If the super

hjlf

Answer:

You are at the top of the Empire State Building on the 102nd floor, which is located 373 m above the ground when your favorite superhero flies over the building parallel to the ground at 70.0% the speed of light.

You have never seen your favorite superhero in real life. Out of curiosity you calculate her height to be 1.57 mm . If the superhero landed next to you, how tall would she be when standing?

Step-by-step explanation:

so this problem is from Einstein's special theory of relativity about length contraction.

the formula is given by:

$L'=L\sqrt{1-\beta^2 }$