What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2,
1 answer:
The equation of the line in point-slope form is: C. y − 5 = −(x − 2).
<h3>What is the Point-Slope Equation of a Line?</h3>A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).
Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:
Slope (m) = rise/run = 3 units/3 units = 1
Negative reciprocal of 1 is -1.
The slope of the line would be m = -1.
Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:
y - 5 = -1(x - 2)
y − 5 = −(x − 2)
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9514 1404 393
Answer:
3x -4y = -9
Step-by-step explanation:
Multiply by 4 to clear the fraction.
4(y -6) = 3(x -5)
Subtract the left-side term to get variables on the same side, with a positive x-coefficient.
0 = 3(x -5) -4(y -6)
Eliminate parentheses and collect terms.
0 = 3x -15 -4y +24
0 = 3x -4y +9
Subtract 9 and swap sides to get standard form.
3x -4y = -9
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Standard form is ...
ax +by = c
where a ≥ 0, and a, b, c are mutually prime integers. If a=0, then b > 0.
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The attached graph shows the equations give the same line. The original line is shown dotted so that you can see they overlap.
