Question

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)? y 5 = x 2 y − 2 = x − 5 y − 5 = −(x − 2) y 2 = −(x 5)

Answer 1

The equation of the line in point-slope form is: C. y − 5 = −(x − 2).

What is the Point-Slope Equation of a Line?

A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).

Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:

Slope (m) = rise/run = 3 units/3 units = 1

Negative reciprocal of 1 is -1.

The slope of the line would be m = -1.

Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:

y - 5 = -1(x - 2)

y − 5 = −(x − 2)

Learn more about point-slope form on:

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