Answer:
A(max) = (9/2)*L² ft²
Dimensions:
x = 3*L feet
y = (3/2)*L ft
Step-by-step explanation:
Let call "x" and " y " sides of the rectangle. The side x is parallel to the wall of the house then
Area of the rectangle is
A(r) = x*y
And total length of fence available is 6*L f , and we will use the wall as one x side then, perimeter of the rectangle which is 2x + 2y becomes x + 2*y
Then
6*L = x + 2* y ⇒ y = ( 6*L - x ) /2
And the area as function of x is
A(x) = x* ( 6*L - x )/2
A(x) = ( 6*L*x - x² ) /2
Taking derivatives on both sides of the equation we get:
A´(x) = 1/2 ( 6*L - 2*x )
A´(x) = 0 ⇒ 1/2( 6*L - 2*x ) = 0
6*L - 2*x = 0
-2*x = - 6*L
x = 3*L feet
And
y = ( 6*L - x ) /2 ⇒ y = ( 6*L - 3*L )/ 2
y = ( 3/2)*L feet
And area maximum is:
A(max) = 3*L * 3/2*L
A(max) = (9/2)*L² f²
Answer:
<em>A.(for weight in pounds)</em>
3, 4, 5, 6, 7
Median: 5
Mode: There are no mode in the following data set.
Mean: 3 + 4 + 5 + 6 + 7 = 25/5 = 25
<em>B.(for number of computers)</em>
4, 8, 18, 25, 45
Median: 18
Mode: There are no mode in the following data set.
Mean: 4 + 8 + 18 + 25 + 45 = 100/5 = 20
~hope this helps~
I would highly appreciate it if you b=would give me the brainliest~ :)
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<h2><em>hope </em><em>it</em><em> helps</em><em>!</em></h2>
