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3 years ago

What is 7/9 ×3 in simplest form?

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

7/9*3=7/9*3/1=7/2 the three divided the nine and seven divided by one is still seven

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Help me please....ASAP...................................

Marysya12 [62]

Area of square = 5 x 5 = 25 cm^2
area of rectangle = 25 x 10 = 250 cm^2
area of figure = 25 + 250 = 275 cm^2

hope it helps

6 0

3 years ago

3). What is the area of a rectangular window measuring 36 inches across 25 points

irina1246 [14]

To find the area of a rectangle, just multiply the dimensions.

x60

360

1800

2160

The area of the rectangle is 2,160 in sq

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3 years ago

WILL GIVE BRAINLIEST!!!!!!!!-What is the recursive rule for this geometric sequence?

dezoksy [38]

I just learned this, I believe that the answer is <span>a1=21;an=7⋅an−1</span>

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3 years ago

Read 2 more answers

A pole that is 3m tall casts a shadow that is 1.3m long. At the same time, a nearby building casts a shadow that is 41.75m long.

8090 [49]

Answer:We're looking for a,b such that

\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}

Step-by-step explanation:

6 0

3 years ago

When testing for current in a cable with eight color-coded wires, the author used a meter to test five wires at a time. How man

balu736 [363]

Answer:

56 different tests

Step-by-step explanation:

Given:

Number of wires available (n) = 8

Number of wires taken at a time for testing (r) = 5

In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.

So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

$^nC_r=\frac{n!}{r!(n-r)!}$

Plug in the given values and solve. This gives,

$^8C_5=\frac{8!}{5!(8-5)!}\\\\^8C_5=\frac{8\times 7\times 6\times 5!}{5!\times 3\times2\times1}\\\\^8C_5=56$

Therefore, 56 different tests are required for every possible pairing of five wires.

6 0

3 years ago