Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = ![\frac{1}{2}(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BAD%7D%29)
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= ![\frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BTotal%20number%20of%20segments%20measuring%20greater%20than%203%7D%7D%7BTotal%20number%20of%20segments%7D)
= ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
= 0.6
Answer:
19
Step-by-step explanation:
PEMDAS
no parenthesis
no exponents
4-6+2 x 7
4-6+ 17
no division
4-6=2
2+17
19 is the answer
Answer:
c. 32 ounces
Step-by-step explanation:
Given that:
The weight of the Spot = 12 ounces
The weight of Rascal = 9.5 ounces; &
The weight of Socks = 10.2 ounces.
To find the litters' total weight, we will sum all the given number of the puppies.
i.e. Total weight of the litter = (12 + 9.5 + 10.2) ounces
Total weight of the litter = 31.7 ounces
Total weight of the litter
32 ounces to the correct number of significant figures.
The answer is B. There can not be any alike "x" inputs.
Answer:
1/4 is ur answer :)
Step-by-step explanation:
Hoped It Helped