Siince 2nd equation is already equal a, subsitute b-2 for a in the other equation
b-2-3b=28
-2-2b=28
add 2 to both sides
-2b=30
divide both sides by -2
b=-15
sub back
a=b-2
a=-15-2
a=-17
(a,b)
(-17,-15)
3rd choice
<span>6 + 2x = 24
2x = 18
x = 9
answer
9
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</span><span>3x – 5 ≥ 7
3x </span>≥ 12
x ≥ 4
answer
<span>{4, 5, 6}
</span>
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<span>4x – 3 ≥ 5
</span><span>4x ≥ 8
</span><span>x ≥ 2
answer
</span><span>{2, 3, 4}
</span>
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<span>3r ≤ 4r – 6
r </span> ≥ 6
answer
<span>{6, 7, 8, 9,10}</span>
4/5= 4 x 2=8
5 x 2=10
5/8=5 x 3 =15
6 x 3= 18
Answer:
B. 2.2π m² : 3.2π m²
Step-by-step explanation:
Given:
Slant height (l) = 2.2 m
Diameter (d) = 2 m
Radius (r) = ½(2) = 1 m
Required:
Lateral area and surface area
Solution:
✔️Formula for lateral area of a cone = πrl
Plug in the values
Lateral area of the cone = π*1*2.2
Lateral area = 2.2π m²
✔️ Formula for surface area of a cone = πr(l + r)
Plug in the values
Surface area of the cone = π*1(2.2 + 1)
Surface area = π(3.2)
Surface area = 3.2π m²
The answer would therefore be:
2.2π m² : 3.2π m²
<h3>
Answer: Choice D</h3><h3>
m = n</h3><h3>
b = sqrt(pi)*a</h3>
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Explanation:
Each circle has a radius of 'a'. So r = a.
The area of each circle is pi*r^2 = pi*a^2
The area of each square with side length b is b^2
The two stacks have the same volume only when the circle area is equal to the square area, so whenever pi*a^2 = b^2 is true.
Solving for b leads to b = sqrt(pi*a^2) = sqrt(pi)*a
The stacks must also be the same height for the volumes to be the same, so m = n as well.
