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Genrish500 [490]
2 years ago
8

Can someone help me out with this problem

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
8 0

From the given options the options B and C are correct for the given equation.

we have given the equation,

70=10+12r

We have to determine the correct option

<h3>What is the equation?</h3>

An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign.

Therefore from the given options the options B and C are correct for the given equation.

To learn more about the equations visit:

brainly.com/question/2972832

#SPJ1

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The daily dinner bills in a local restaurant are normally distributed with a mean of $28 and a standard deviation of $6. What ar
Degger [83]

Answer:

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 6

What are the minimum value of the bill that is greater than 95% of the bills?

This is the 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 28}{6}

X - 28 = 6*1.645

X = 37.87

The minimum value of the bill that is greater than 95% of the bills is $37.87.

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