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ollegr [7]
3 years ago
14

PLZ HELP ME WITH THIS...!

Mathematics
1 answer:
miv72 [106K]3 years ago
5 0

Answer: 1/3


Step-by-step explanation: To find the y- intercept of any function substitute the 0 for x and solve for y


Hope this helps!


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61,361 rounded to the nearest hundred
yanalaym [24]
61,400 is the answer. Since 61 is closer to 100 than 0, you round up.
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What’s this answer ????????
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2= f/8

Mutiply both sides by 8

(2/(8)= 16

f/8(8)= f ( crossed out 8 and 8)

Answer: f= 16

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Complete the ratio<br> 4 : 32 = 1 : ?
zavuch27 [327]

Answer:

1: 8

Step-by-step explanation:

4 : 32

Divide both the left and right side by 4

4/4 =1

32/4 = 8

4:32  becomes  1:8

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(-2,0) And (a,3) <br> Slope 3 Over 8
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8 0
3 years ago
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
3 years ago
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