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dexar [7]
1 year ago
5

Consider a TV set that consumes 120 W of electric power when it is on, and is kept on for an average of 6 h per day. For a unit

electricity cost of 23 cents per kWh, determine the cost of electricity this TV consumes per month (30 days). The cost of electricity the TV consumes per month is $
Mathematics
1 answer:
Andru [333]1 year ago
3 0

The cost of electricity consumed by the TV per month is <u>$4.968</u>.

In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.

We are asked to find the cost of electricity the TV consumes in the month.

The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.

The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.

Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.

Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.

Learn more about computing costs at

brainly.com/question/14277272

#SPJ4

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line y = 2x+1 is transformed by a dialation with a scale factor of two and centered at (0,-4). what is the equation of the image
Gekata [30.6K]

Answer: y = 2x + 6

Step-by-step explanation:

Here the equation of line,

y = 2x + 1

y-intercept of the line is, (0, 1)

And, the slope of the line is 2.

Since, If a point (x,y) is dilated by a scale factor k about a point (a,b),

Then transformed point are get by,

(x,y)\rightarrow (k(x-a)+a, k(y-b)+b)

Thus, The transformed point of point (0,1) when dilation is occur by the scale factor 2 about the point (0,-4),

(0,-4)\rightarrow (2(0-0)+0, 2(1+4)-4)

(0,-4)\rightarrow (0, 6)

Thus, the point of the new line is (0,6)

And, the slope of the new line is 2 ( because in the dilation, the slope of the line does not change)

Thus, the equation of new line,

(y - 6) = 2 (x - 0)

y - 6 = 2x

y = 2x + 6


5 0
3 years ago
What is the probability of selection for any man in a proportionate random sample, where a sample of 100 will be drawn from a po
kolbaska11 [484]
Working Principle: Stratified Random Sampling

nx = (Nx/N)*n

where:
    nx = sample size for stratum x
    Nx = population size for stratum x
    N = total population size 
    n = total sample size

Given:

  Nx = 100
  N = 1000
  n = 0.5*(1000) = 500

Required: Probability of Man to be selected

Solution:

nx = (Nx/N)*n
nx = (100/1000)*500 = 50 men

ny = (Nx/N)*n
ny = (100/1000)*500 = 50 women


Probability of Man to be selected = nx/(nx + ny)*100 = 50/(50+50)*100 = 50%

<em>ANSWER: 50%</em>
7 0
3 years ago
Can someone help me with this please? Thank you!
Finger [1]

Answer:

528 cm²

Step-by-step explanation:

First I would calculate the area of the side rectangles:

20 x 9 = 180 cm²

There are two identical rectangles on both sides so i would x2

180 x 2 = 360 cm²

The area of the middle rectangle:

6 x 20 = 120 cm²

The area of the triangles:

Area of a triangle = (Base x Height)/2

8 x 6 = 48

48 ÷ 2 = 24

There are two identical triangles on the bottom and the top so x2

24 x 2 = 48

Now add all the values up:

360 + 120 + 48 = 528 cm²

I hope this helps!

5 0
2 years ago
4x^2-5x-15=0 how to find the vertex and y intercept
mezya [45]
ax^2+bx+c=0\\\\the\ vertex:\left(\frac{-b}{2a};\frac{-(b^2-4ac)}{4a}\right)\\\\y-intrcept=c\\=======================================\\\\4x^2-5x-15=0\\\\a=4;\ b=-5;\ c=-15\\\\\frac{-b}{2a}=\frac{-(-5)}{2\cdot4}=\frac{5}{8};\ \frac{-(b^2-4ac)}{4a}=\frac{-[(-5)^2-4\cdot4\cdot(-15)]}{4\cdot4}=-\frac{265}{16}\\\\\boxed{the\ vertex:\left(\frac{5}{8};-\frac{265}{16}\right)}\\\\\boxed{y-intercept:-15}
5 0
3 years ago
Find the interquartile range of the data.
likoan [24]

The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

4 0
3 years ago
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