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dexar [7]
2 years ago
5

Consider a TV set that consumes 120 W of electric power when it is on, and is kept on for an average of 6 h per day. For a unit

electricity cost of 23 cents per kWh, determine the cost of electricity this TV consumes per month (30 days). The cost of electricity the TV consumes per month is $
Mathematics
1 answer:
Andru [333]2 years ago
3 0

The cost of electricity consumed by the TV per month is <u>$4.968</u>.

In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.

We are asked to find the cost of electricity the TV consumes in the month.

The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.

The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.

Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.

Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.

Learn more about computing costs at

brainly.com/question/14277272

#SPJ4

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Answer:

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Step-by-step explanation:

<u>Decrease in number:</u>

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Doug mcdougal is whipping up 72 different snacks for his 12th annual blooper bowl bash he invited 138 guess but only 16 are comi
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The number of guests coming to Doug McDougal party can be calculated to be 23 people.

<h3>What number of people are coming?</h3>

Doug invited 138 guests and out of this, only 1/6 will be coming.

The number of people coming is therefore:

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Solving gives:

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2 years ago
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S_A_V [24]

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Looking at the ends of the graph, as goes to ∞ or −∞, gets

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b) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as x goes to ∞ or −∞, gets

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c) End behavior: As → ∞, () → ∞, and as → −∞, () → −∞.

Looking at the ends of the graph, as goes to ∞, continues to increase

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