Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
Answer:
c
Step-by-step explanation:
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Answer:
y = 25 - 3x
Step-by-step explanation:
x = 7 - p ⇒ p = 7 - x
y = 3(7-x) + 4
y = 21 - 3x + 4
y = 25 - 3x