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GaryK [48]
2 years ago
12

3 questions in 1

Mathematics
1 answer:
MrRissso [65]2 years ago
3 0

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

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Pls help i will give u brianliest
Fynjy0 [20]

Answer:

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

Step-by-step explanation:

We can take any two input-output pairs from the table to find the equation of given function.

Linear function is given by:

y =mx+b

Here m is the gradient of the functions which is defined as:

m = \frac{rise}{run} = \frac{y_2-y_1}{x_2-x_1}

The input-output pairs are:

(x1,y1) = (-1,-1)

(x2,y2) = (0,-4)

First of all,

m = \frac{-4-(-1)}{0-(-1)}\\= \frac{-4+1}{1} = -3

Putting the value of slope in the equation

y = -3x+b

Putting (-1,-1) in the equation

-1 = -3(-1)+b\\-1 = 3+b\\b = -1-3\\b = -4

The equation will be:

y = -3x-4

Hence,

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

7 0
3 years ago
What’s the answer and the work ?
Phoenix [80]

Answer:

2√14

Step-by-step explanation:

√56

√2^2 x 14

√2^2 √14

2√14

5 0
3 years ago
PLEASE HELP MEE I CAN'T SOLVE THIS BY MYSELF!
UNO [17]

Answer:

x = 22

Step-by-step explanation:

The figure is attached below.

Its given that SV is parallel to RU. We have to find the value of x.

Observe that, if we join point V to U, we will obtain a parallelogram RSVU. One of the properties of a parallelogram is that the sum of its two adjacent angles is always 180 degrees.

So, the two adjacent angles would be: ∠S and ∠R

From the figure:

∠S = 5x + 4

∠R = 44 + x

Since,

∠S + ∠R must be 180 degrees, we can write:

∠S + ∠R  = 180

5x + 4 + 44 + x = 180

6x + 48 = 180

6x = 132

x = 22

Therefore, the value of x is 22.

6 0
3 years ago
Which statement about the following equation is true?<br>2x2-9x+2-1​
Furkat [3]

Complete Question:

Which statement about the following equation is true?

2x^2-9x+2 = -1

A) The discriminant is less than 0, so there are two real roots

B) The discriminant is less than 0, so there are two complex roots

C) The discriminant is greater than 0, so there are two real roots

D) The discriminant is greater than 0, so there are two complex roots

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

The given equation is 2x^2-9x+2 = -1 which by simplification becomes

2x^2 - 9x + 3 = 0

For a quadratic equation of the form ax^2 + bx + c = 0, the discriminant is given by the equation, D = b^2 - 4ac

If the discriminant D is greater than 0, the roots are real and different

If the discriminant D is equal to 0, the roots are real and equal

If the discriminant D is less than 0, the roots are imaginary

For the quadratic equation under consideration, a = 2, b = -9, c = 3

Let us calculate the discriminant D

D = (-9)² - 4(2)(3)

D = 81 - 24

D = 57

Since the Discriminant D is greater than 0, the roots are real and different.

3 0
3 years ago
On a piece of paper, graph y=-3x-2
svet-max [94.6K]
Hope the answer helps!!!
:)

7 0
3 years ago
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