If 3 under is -3 than 3 over would be positive 3
<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>

<em><u>At what times will the object be at a height of 56 feet</u></em>
<em><u>Substitute h = 56</u></em>

Solve the above equation by quadratic formula


Thus, at 2 second and 1.75 second, the object be at a height of 56 feet
2 Five Yard Sides And 2 15 yard sides.
Answer:
7.142m/s
Step-by-step explanation:
Velocity=change is distance/change in time
change in distance=400m-0m=400m
change in time=56-0=56seconds
v=400m/56s
v=7.143m/s