sinx-✓(1-3sin2x)=0
-✓(1-3sin2x)=-sinx
apply squared both sides
(-✓(1-3sin2x)^2=(-sinx)^2
1-3sin2x=sin2x
collect like terms
-3sin2x-sin2x+1=0
-4sin2x+1=0
-4sin2x=-1
devide both sides by -4
sin2x=-1/-4
sin2x=0.25
sinx*sinx =0.25
[sinx]^2 = 0.25
apply square root both sides
<h2>✓(sinx)2 = ✓0.25</h2>
<h2>sinx=0.5</h2><h2> </h2><h2>x=sin^-(0.5)</h2>
<h2>x=30°</h2>
<h3>check quadrant where sin is positive, sin is +ve in second quandrant</h3>
180-x= Theta(X)
180-30=X
X=150°
therefore, all angles for sinx -✓(1-3sin2x)=0 are (X= 30° and 150°)
√49z²
= √(7z)². [ here, Square cancles sq. root]
= 7z
May be Helpful.
Thank you!
C becuase it makes the most sense
H = -16t^2 + 36t + 9
At maximum height h' = 0,
h' = -32t + 36 = 0
32t = 36
t = 36/32 = 1.13 s.
Maximum height = -16(1.125)^2 + 36(1.125) + 9 = 29.25 ft
Answer is option d (1.13 s, 29.25 ft)