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GalinKa [24]
2 years ago
5

What are five ratios that are equivalent to 5÷2v

Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

Answer:

5 : 2

10 : 4

15 : 6

20 : 8

25 : 10

Step-by-step explanation:

Not so sure if this is correct. Please tell me if it is or isn't. I'm sorry if it's wrong.

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What is the value of tan D ?
4vir4ik [10]

Answer:

12/5

Step-by-step explanation:

Tan D = opp/adj = EF/DE = 12/5

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How many friends are sharing the berries?​
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Answer:

not me for sure lol

Step-by-step explanation:

I'm not sure why this is a question

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Brad had a small gathering at a local steakhouse. The steakhouse offers three dinner platters which vary by size and price. They
bonufazy [111]

Answer:

D.) $115

Step-by-step explanation:

9.95 x 4 = 39.8

12.95 x 2 = 25.9

15.95 x 2 = 31.9

39.8 + 25.9 + 31.9 = 97.6

97.6 x 0.18 = 17.568

97.6 + 17.568 = 115.168

115.168 ≈ 115

3 0
2 years ago
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Answer the following automotive services question.
Wittaler [7]

Answer:

V=RI

R=V/I

R=12/0.6

=12×10/6

=20 ohm s

7 0
3 years ago
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
Read 2 more answers
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