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marishachu [46]
3 years ago
15

Let f(x)=201+9e−3x .

Mathematics
2 answers:
Rudik [331]3 years ago
7 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

f(x)=\frac{20}{1+9e^{-3x}}

As we know that it is a logistic function, and there are two types of growth rate :

1) Increasing Growth rate .

2)Diminishing  Growth rate .

Here, Carrying capacity = 20

So, at half of its carrying capacity growth rate changes.i.e.

at y>10, there is diminishing growth rate.

AT y<10, there is increasing growth rate.

so, put y=10

so, it becomes,

10=\frac{20}{1+9e^{-3x}}\\\\1+9e^{-3x}=\frac{20}{10}=2\\\\9e^{-3x}=2-1\\\\9e^{-3x}=1\\\\e^{-3x}=\frac{1}{9}\\\\\text{Taking logrithms on both sides,}\\\\-3x=\ln 1-\ln9\\\\-3x=-\ln 9\\\\3x=\ln 9\\\\x=\frac{\ln 9}{3}

So, the interval will be (\frac{ln9}{3},\infty)

Above this there will growth rate at a decreasing rate and below this the growth rate at a increasing rate.

Hence, Third option is correct.

Licemer1 [7]3 years ago
5 0

Answer:

f(x)=20/1+9e^-3x

C. (ln9/3, ∞)

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4 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2: S
Anna35 [415]

Answer:

The 98% confidence interval for the population proportion of disks which are defective is (0.082, 0.118).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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3 years ago
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