What is y = 24 + 234*293084

Please help with all 3

DerKrebs [107]

Answer:

1, volume=23×9×5

=1035

2, volume=(1/2×5×4)×20

... =200

3.

8 0

3 years ago

Read 2 more answers

I’m thinking of three consecutive odd integers. When I add the larger two the result is nine less than three times the smallest

maksim [4K]

Answer:

Step-by-step explanation:

Let the 3 consecutive odd numbers be n, n+2, n+4.

(n+2) + (n+4) = 3n - 9

Collect like terms

n+n-3n=-9-6

-n=-15

n=15,

n+2=17

n+4=19

4 0

3 years ago

5.75 - 1 2 (20 ÷ 2.5) ÷ 2 + 6

Mazyrski [523]

Answer:

-48.25

Step-by-step explanation:

You will start by using PEMDAS- Parenthesis-Exponent-Multiplication-Division- Addition-Subtraction

$5.75-12(20/2.5)/2+6\\5.75-12(8)/2+6\\5.75-96/2+6\\5.75-48+6\\5.75-54= -48.25$

6 0

3 years ago

Which symbol correctly compared these two fractions

rodikova [14]

Answer:

B

Step-by-step explanation:

> = greater than

= this means equal to

< = less than

$\frac{8}{13} =\frac{8}{13}$

4 0

3 years ago

Confidence Interval Mistakes and Misunderstandingsâ€”Suppose that 500 randomly selected recent graduates of a university were as

kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

$n=500\\\bar x=8.6\\\sigma=2.2$

(a)

The (1 - α)% confidence interval for population mean (μ) is:

$CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

$8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)$

(b)

The (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

n = 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0

3 years ago