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FromTheMoon [43]
4 years ago
14

(SAT Prep) In the figure, if PN = LN, NP ∥ MQ, and QL bisects ∠PQM, what is value of x?

Mathematics
1 answer:
sergejj [24]4 years ago
6 0

Answer:

  x = 67°

Step-by-step explanation:

The angle at N is the supplement to 54°, so is 126°. That makes the base angles of isosceles triangle LNP equal to (180 -126)°/2 = 27°. Then angle MLQ is ...

  ∠MLQ = 180° -70° -27° = 83°

and angle MQL is ...

  ∠MQL = 180° -83° -54° = 43°

Angle LQP is that same measure, by virtue of the angle bisector LQ, so the measure of angle x is ...

  x = 180° -43° -70°

  x = 67°

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Answer:

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Item 25
MArishka [77]

Answer:

m =\frac{y_2 -y_1}{x_2-x_1}= \frac{5425-3733}{3-0}= 564

Now we can use the value for 1994 and we can find the intercept like this:

3733 = 564*0 +b

And solving for b we got:

b = 3733 -0= 3733

So then oir model would be given by:

y= 564x +3733

Option C

Step-by-step explanation:

For this case we want to create a linear function for the the value of  the investment in the vear x, where x =0 represents 1994.

We know that for 1994 (x= 0) the value is y = $3733 and for 1997 (x=3) the value of y = $5425

We want to find a model given by:

y = mx +b

Where m is the slope and b the intercept. We can find the slope with this formula:

m =\frac{y_2 -y_1}{x_2-x_1}= \frac{5425-3733}{3-0}= 564

Now we can use the value for 1994 and we can find the intercept like this:

3733 = 564*0 +b

And solving for b we got:

b = 3733 -0= 3733

So then oir model would be given by:

y= 564x +3733

Option C

4 0
4 years ago
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