Question

The sum of 5 consecutive even integers is 4 less than the sum of the first 8 consecutive odd counting numbers. What is the smallest of the even integers

Answer 1

The smallest of the even integers is 8.

It is a well-known fact that the sum of the first n odd numbers is n^2. This makes the sum of the first 8 odd numbers equal to 64.

Let n be equal to the smallest of the 5 even integers. Then (n+2) is the next highest, (n+4) even higher, and so on.

This sets up the equation n+(n+2)+(n+4)+(n+6)+(n+8)+4=64

Now we solve:

5n+24 = 64

5n = 40

n = 8

The smallest of the even integers is 8.

Learn more about integers here: brainly.com/question/14453211

#SPJ4