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sladkih [1.3K]
2 years ago
7

Calculate: 6666666x666666/1+2+3+4+5+6+5+4+3+2+1- 777777x777777/1+2+3+4+5+6+7+6+5+4+3+2+1

Mathematics
2 answers:
barxatty [35]2 years ago
8 0

Answer: 3.8395025e+12

Lol

GrogVix [38]2 years ago
6 0

3839502493910

Step-by-step explanation:

you will multiple the 6 and the 7 digits and the other digits

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Please help.
m_a_m_a [10]

Answer:

26.2

Step-by-step explanation:

PQ/QR = 8/16 = 0.5

tan(26.6) = 0.5

7 0
4 years ago
A rectangular prism has a length of 18 feet, a height of 14 feet, and a width of 2 feet. What is its volume, in cubic feet?
Fittoniya [83]

Answer:

504

Step-by-step explanation:

14x18x2=

(14x18)x2=

252x2=

504

6 0
2 years ago
Read 2 more answers
What is 0.25 divided by 1.075?
timurjin [86]
0.25 divided by 1.075 is 0.2325..
But I think 1.075 divided by 0.25 sounds more right, in case that is the problem then the answer is 4.3
4 0
3 years ago
a store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for 27.93 and large bags cost 66.98.w
Nonamiya [84]

Answer

Find out the ratio of price to pound for each bag.

To prove

As given

A store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for $27.93 .

7 pound = $27.93

Now find out the cost for the 1 pound.

1\ pound\ cost= \frac{27.93}{7}

1 pound cost = $3.99

As given large bags cost $66.98.

Now find out pounds in the large bags.

Let us assume that the number of pounds in the large bags be x.

Than

3.99 × x = 66.98

x = \frac{66.98}{3.99}

x = 16.8 pounds (approx)

Now find out the ratio of  price to pound for each bag.

As small bags weight = 7 pounds

Cost of the small bags = $27.93

\frac{Price\ of\ small\ bag}{Cost\ of\ the\ small\ bags} = \frac{27.93}{7}

As large bags weight = 16.8 pounds

Cost of the large bags = $66.98

\frac{Price\ of\ large\ bag}{Cost\ of\ the\ large\ bags} = \frac{66.98}{16.8}

Hence proved


7 0
3 years ago
Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
3 years ago
Read 2 more answers
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