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klio [65]
3 years ago
11

One to one relationships describe situations where people are matched with with unique identities, such as their Emirates ID num

ber. A function is a relation that matches x-values to y-values. What do you suppose a one to one function is?
Mathematics
1 answer:
GuDViN [60]3 years ago
4 0

A one to one function is a function which matches <em>exactly one </em>x value with <em>exactly one </em>y value. The fancy term for this is an <em>injective function</em>.

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The product of two rational numbers is 2/5 , if one of them is -8/25, find the other.
Sergio [31]

Answer:

x=-5/4

Step-by-step explanation:

Let the number be  x and y

     x.y=2/5    (The product of two rational numbers is 2/5)

if  one of the number is  -8/25

x.(-8/25)=2/5

(Here Substituted the value of one of the number yoy may substitute the value -8/25 in place of x

x=(2/5) *(-25/8)    

x=-5/4  

3 0
2 years ago
Read 2 more answers
-1 3/7 x (-3 2/3)=?
xxTIMURxx [149]
I was not sure if the x in your equation was a multiplication sign or a variable
6/7x
-1 multiplied by 3/7x times -2
And when you multiply two negatives it equals a posible so the -2 and -1 turn into a positive
6 0
3 years ago
I need help with number 16 i need the answer by 8:45 please. Thank you
Nadusha1986 [10]
Type o ( ii)        =   6 . 25 

Type A ( l^A l ^A    or l ^A i )    = 18 . 75 

Type B   ( l ^b l^b  or l ^ bi )   = 18.75

Type AB ( l ^ A l^ B)    = 56.25 

3 0
3 years ago
What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?
WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

To find:

The completely simplified sum of the polynomials.

Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y

Sum=-2xy^5+3x^4y+3x^2y^2

Therefore, the sum of the given polynomials is -2xy^5+3x^4y+3x^2y^2. It is a polynomial with degree 6 and leading coefficient -2.

5 0
3 years ago
The formula for the volume of a right triangular pyramid is V = 1/6 bhx, where b is the base of the triangle, h is the height of
charle [14.2K]
Answer: x = 6V/bh

Explanation:

V = 1/6 bhx
V = (bh/6)x
V • 6/bh = x
6V/bh = x
6 0
3 years ago
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